Option 1 : 49 litres

The initial quantity of mixture = 343 litres

Initial ratio of mixture = 5 : 2

The final ratio of mixture = 5 : 3

Initial quantity of wine = 5 units

Initial quantity of water = 2 units

According to the question,

(5 + 2) units = 343 litres

⇒ 7 units = 343 litres

⇒ 1 unit = 49 litres

From the initial and final ratio of the mixture, we can see that quantity of water is increased by 1 unit.

So, the quantity of water added = 1 unit

⇒ 49 litres

∴ The quantity of water added is 49 litres.

Traditional Method:

**Given:**

The initial quantity of mixture = 343 litres

Initial ratio of mixture = 5 : 2

The final ratio of mixture = 5 : 3

**Calculation:**

Let initial quantity of wine and water be 5x and 2x.

5x + 2x = 343

⇒ 7x = 343

⇒ x = 49

Initial quantity of wine = 5x

⇒ 5 × 49

⇒ 245 litres

Initial quantity of sugar = 2x

⇒ 2 × 49

⇒ 98 litres

Let the water to be added in new mixture be x litres.

According to the question,

245/(98 + x) = 5/3

⇒ 245 × 3 = 5(98 + x)

⇒ 735 = 490 + 5x

⇒ 5x = 245

⇒ x = 49

**∴ The quantity of water added is 49 litres.**