This question was previously asked in

SSC CGL Tier-II ( JSO ) 2016 Official Paper ( Held On : 2 Dec 2016 )

Option 2 : 0.433

Cell

306304

10 Questions
10 Marks
7 Mins

**Given**

m = 4

**Formula**

The probability distribution is given by

p(x) = (e^{-m} × m^{x})/x!

**Calculation**

According to the formula

⇒ p(x0 = (e^{-4} × 4^{x})/x!

Now the probability that in a given month there will be less than 4 acc idents

⇒ P(0) + P(1) + P(2) + P(3)

⇒ \(\mathop \sum \limits_{x = 0}^{x = 3} \)e^{-4} 4^{x}/x! = e^{-4}[1 + 4 + 8 + 32/3]

⇒ 0.0183 × [13 + 32/3

⇒ 0.0183 × 71/3

**∴ The probability that in a given month there will be less than 4 accidents is 0.4331**